Question

Prove that the diagonals of a

rectangle with vertices (0, 0), (a, 0),

(a, b) and (0, b) bisect each other and

are equal.​

Answer 1

Answer:

Heya mate ur answer

Step-by-step explanation:

let A (0,0) B (a,0) C (a, b) and D (0, b)

here AC and BD is diagonal of rectangle .

midpoint of AC

use section formula

{(0+a)/2, (0+b)/2}=(a/2, b/2)

also find midpoint of BC

{(a+0)/2,(0+b)/2}=(a/2, b/2)

we see

midpoint of AC =midpoint of BD

hence midpoint of both diagonals meet at a same point (a/2, b/2)

so, we can say that diagonals of a rectangle bisect each other are equal.

Answer 2

hope this helps u

refer the attachment below