Question

prove that the diagonals of a rhombus are perpendicular to each other.​

Answer 1

Answer:

Proof that the diagonals of a rhombus divide it into 4 congruent triangles

In rhombus ,  is the point at which the diagonals intersect.

Since the diagonals of a rhombus are bisectors of eachother,  and .

Also, all sides are congruent.

By the SSS Postulate, the 4 triangles formed by the diagonals of a rhombus are congruent.

Proof that the diagonals of a rhombus are perpendicular

Continuation of above proof:

Corresponding parts of congruent triangles are congruent, so all 4 angles (the ones in the middle) are congruent.

This leads to the fact that they are all equal to 90 degrees, and the diagonals are perpendicular to each other.

Explanation:

Please mark me as brainliest. please