Question

prove that the diagonals of a rhombus bisect each other at right angle

Answer 1

Answer:

Step-by-step explanation:

There are of 90°

Answer 2

Answer:

Let ABCD be a rhombus

so

AB= BC= CA = AD ( WHY ? FIND YOURSELF )

NOW

LET THE BISECTORS OF THE RHOMBUS

MET AT THE POINT O

FROM ∆ AOD AND ∆ AOB

AB = AD

OD = OB

AO = AO

Therefore ∆AOD ~= ∆AOB

so angle AOD = angleAOB

BUT

angleAOD + angleAOB = 180 DEGREE

2AOD = 180

AOD = 90

PROVED