Prove that the diameter of dark ring is equal to ssquare root of natural number.
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An air film of varying thickness is formed between the lens and the glass sheet. The diameter of dark rings is proportional to the square root of natural numbers while bright rings are proportional to the square root of odd natural numbers hence the don't increase at the same rate.
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Answer:
An air film of varying thickness is formed between the lens and the glass sheet. The diameter of dark rings is proportional to the square root of natural numbers while bright rings are proportional to the square root of odd natural numbers hence the don't increase at the same rate.
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