Math, asked by honeygarg1288, 11 months ago

Prove that x^2-y^2=c(x^2+y^2)^2 is the general solution of the differential equation: (x^3-3xy^2 )dx=(y^3-3x^2 y)dy, where c is a parameter

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Answered by pratikkumar12
0

Step-by-step explanation:

Prove that x^2-y^2=c(x^2+y^2)^2 is the general solution of the differential equation: (x^3-3xy^2 )dx=(y^3-3x^2 y)dy, where c is a parameter

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