Prove that the equation 3mx² – (2m + 3n) x + 2n=0 has rational roots
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Answer:
f(2)=3×4-4m+2n
0=12-4m+2n
-4m+2n=-12..eq (1)
f(3)=27-6m+2n=0
-6m+2n=-27... eq (2)
eq(1)-(2)
2m=15
m=15/2
put m=15/2 in eq (1)
-4×15/2+2n=-12
-30+2n=-12
2n=18
n=9
m=15/2: n=9
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