Question

Prove that the equation x3 + x − 1 = 0 has exactly one real root.

Answer 1

Answer:

0.5

Step-by-step explanation:

$3x + x - 1 = 0 \\ 4x - 1 = 0 \\ 4x = 1 \\ x = \frac{1}{4} \\ x = 0.25 \\ = \sqrt{0.25} =0 .5$