prove that the figure obtained by joining the mid points of the adjacent sides of a quadrilateral is a parallelogram
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Hello Mate!
Given : The figure is obtained by joining mid points of quadrilateral.
To prove : EFGH is ||gm
To Construct : Join BD.
Proof : Since E and F are mid points in triangle ABD,
=> EF || BD and EF = 1 BD / 2 __(1)
Since G and H are mid points in triangle BCD,
=> GH || BD and GH = 1 BD / 2 ___(2)
From equation (1) and (2) we get
=> EF || GH and EF = GH.
Hence a quadrilateral whose a pair of side is equal and parallel is parallelogram.
Hence proved.
Have great future ahead!
Given : The figure is obtained by joining mid points of quadrilateral.
To prove : EFGH is ||gm
To Construct : Join BD.
Proof : Since E and F are mid points in triangle ABD,
=> EF || BD and EF = 1 BD / 2 __(1)
Since G and H are mid points in triangle BCD,
=> GH || BD and GH = 1 BD / 2 ___(2)
From equation (1) and (2) we get
=> EF || GH and EF = GH.
Hence a quadrilateral whose a pair of side is equal and parallel is parallelogram.
Hence proved.
Have great future ahead!
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abigail9:
what is the shape of the outer figure??
Outer shape is quadrilateral, any figure which has 4 sides.
ok thnx
always welcome
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hope you find it helpful dude
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