Question

prove that the given equation.​

Answer 1

Answer:

Prove That :

$\frac{sin(x + y)}{sin(x - y)} = \frac{tan \: x + tan \: y}{tan \: x - tan \: y}$

Proof :

$\frac{sin \: x + sin \: y}{sin \: x - sin \: y }$

Dividing Numerator and Denominator by Cos x . Cos y

$\frac{sin \: x +sin \: y }{cos \: x \times cos \: y} \div \frac{sin \: x - sin \: y}{cos \: x \times cosy}$

$\frac{tan \: x + tan \: y}{tan \: x - tan \: y}$

Proved