prove that the height of a tower is 6 m when angle of elevation from top of the tower to two points 4m and 9m away from bottom of the tower is complementory
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Figure is in the attachment.
In ABC = Tan(90-Ф) = CotФ
CotФ = AB\BC
1\TanФ = AB/BC
TanФ = BC/AB------------------(1)
In ABD
TanФ = AB/BD-------------------------(2)
From (1) and (2)
AB\BD = BC/AB
AB² = BC*BD
AB = √9*4
AB = √36
AB = 6cm
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