Prove that the interior angles of polygon is 360 degrees
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exterior angle + interior angle = 180°So, for polygon with 'n' sidesLet sum of all exterior angles be 'E', and sum of all interior angles be 'I'.E+I= n × 180°E =n×180° - ISum of interior angles is (n-2)×180°E = n × 180° - (n -2) × 180°.E= n × 180° - n × 180° + 2 × 180°E= 180°n - 180°n + 360°E= 360°Hence, The sum of all the exterior angles of a polygon is 360° .
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The sum of all interior angle of polygons is equal to 360 because u add the exterior and interior to get 180, multiply it by 2 and get n = 360
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