Math, asked by satrox94261, 1 year ago

Prove that the lengths of tangents drawn from an external point to a circle are equal. 19

Answers

Answered by guptarashi0790p9lgj0
0
This is the answer for your question. Now please can you please mark it as brainliest answer
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Answered by fanbruhh
5
\huge\bf{hey }

\huge{ \mathfrak{ \pink{here \: is \: answer}}}

\bf{ \green{given}}

tangent AB and AC are on points B and C.

\bf{to \: prove}
AB=AC

\bf{ \blue{construction}} <br />
join O to A

O to C

and..

O to B

\bf{ \purple{proof}
\sf{in \triangle \: aoc \: and \: \triangle \: aob}
\sf{ \angle \: oca = \angle \: oba( \: both \: 90 \degree)}
\sf{ob = oc \: \: (radius \: of \: circle)}
\sf{oa = oa \: (common)}
\sf{ hence\: \triangle \: aoc \: \cong\: \triangle \: aob(by \: rhs)}

hence

\bf{ab = ac \: \: (cpct)}

\huge{lhs \: = \: rhs}
\bf{ \underline{proved}}

\huge \boxed{ \boxed{ \orange{hope \: it \: helps}}}
\huge{ \gray{thanks}}
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