Prove that the line joining the mid point of two equal chord of a circle subtend equal angle with the chord
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aryandesi:
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HEY MATE HERE IS YOUR ANSWER!!!
● GIVEN :- AB and CD are two equal chords of circle with centre O and radius r.
E and F are the midpoint of chords AB and CD.
● TO PROVE :- Angle AEF = Angle CFE
Angle BEF = Angle DFE
● CONSTRUCTION :- Join OE and OF
● PROOF :- E and F are the midpoints of AB and CD respectively.
therefore OE is perpendicular to AB and OF perpendicular to OF
Angle OEF=Angle OFE
90- Angle OEF = 90 - Angle OFE
AND 90 + Angle OEF = 90 + Angle OFE
therefore, Angle AEF = Angle CFE
Angle BEF = Angle DFE
HOPE IT HELPS YOU!!!
● GIVEN :- AB and CD are two equal chords of circle with centre O and radius r.
E and F are the midpoint of chords AB and CD.
● TO PROVE :- Angle AEF = Angle CFE
Angle BEF = Angle DFE
● CONSTRUCTION :- Join OE and OF
● PROOF :- E and F are the midpoints of AB and CD respectively.
therefore OE is perpendicular to AB and OF perpendicular to OF
Angle OEF=Angle OFE
90- Angle OEF = 90 - Angle OFE
AND 90 + Angle OEF = 90 + Angle OFE
therefore, Angle AEF = Angle CFE
Angle BEF = Angle DFE
HOPE IT HELPS YOU!!!
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