Prove that the line joining the midpoints of the two parallel chirds pass through the centre
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Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB.
⇒ OP ⊥ AB
⇒ ∠APO = ∠BPO = 90°
But OX | | AB
∴ ∠POX = ∠APO [alternate interior angle]
⇒ ∠POX = 90°
Similarly, ∠XOQ = 90°
Now, ∠POX + ∠XOQ = 90° + 90° = 180°
so, POQ is a straight line . Hence proved
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