Question

prove that the line segment joining the mid point of the hypotenuse of a right angled triangle to its opposite vertex is half of the hypotenuse

Answer 1

use pythagorous theorem

Answer 2

Let the ∆ABD
Dear is the midpoint
DB is joined
D is the midpoint so,AD=CD =AD=1/2of AC....1
In ∆ABD
Draw perpendicular bisector of AB that is DE
Now,In∆ ADE and BDE,we have
AE=BE(d is mid point)
Angle AED=Angle BED(each 90)
DE=DE(common)
By SAS ∆s are congruent
By CPCT AD=BD
So,BAD is 1/2 of AC from ..1
Thanks
I think it will help you or may
give u some idea of doing.