Question

Prove that the line which cuts intercepts on
axes are 4 and 3 respectively passes through the
point (0, 3).​

Answer 1

Answer:

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Answer 2

Question:

Prove that the line which cut the intercepts on the axis are 4 and 3 respectively passes through the point (0,3).

Note:

• The x,y-intercept form of a straight line is given by ; x/a + y/b = 1 , where a is the x-intercept and b is the y-intercept. Also, the point of interception on x-axis is (a,0) and the point of the interception on y-axis is (0,b).

• If the coordinates of a point satisfy the equation of a line then we can say that the line passes through that point.

Solution:

Here,

It is given that;

x-intercept = 4

y-intercept = 3

Thus,

The equation of the straight line with x-intercept=4 and y-intercept=3 ,will be given by;

=> x/4 + y/3 = 1

=> (3x + 4y)/12 = 1

=> 3x + 4y = 12 --------(1)

Now,

Let's put the coordinates of the given point (0,3) in the obtained equation of straight line.

{ ie; put x = 0 and y = 3 in eq-(1) }.

=> 3x + 4y = 12

=> 3•0 + 4•3 = 12

=> 0 + 12 = 12

=> 12 = 12

=> LHS = RHS

Hence,

The the line 3x + 4y = 12 passes through the given point (0,3).