Question

- Prove that the lines 2x + 3y - 4z = 0.3x - 4y + z = 0 and 5x
- 0,*-7y + 5z - 6 - 0 are parallel
3
+ 12​

Answer 1

answer= Let's solve for x.

x=−1.764706y+2.352941z

Step-by-step explanation:

Let's solve for x.

2x+3y−4z=0.3x

Step 1: Add -0.3x to both sides.

2x+3y−4z+−0.3x=0.3x+−0.3x

1.7x+3y−4z=0

Step 2: Add -3y to both sides.

1.7x+3y−4z+−3y=0+−3y

1.7x−4z=−3y

Step 3: Add 4z to both sides.

1.7x−4z+4z=−3y+4z

1.7x=−3y+4z

Step 4: Divide both sides by 1.7.

1.7x

1.7

=

−3y+4z

1.7