Prove that the lines 3x – 2y + 5 = 0 and 4x + 6y – 23 = 0 are perpendicular.
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In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.
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Slope of a line ax+by+c=0 Is -(b/a)
Therefore
Slope of first line = -(-2/3) = 2/3 ——>m1
Slope of second line = -(6/4) = -3/2—>m2
Since m1 x m2 = -1
====> The lines are perpendicular
Therefore
Slope of first line = -(-2/3) = 2/3 ——>m1
Slope of second line = -(6/4) = -3/2—>m2
Since m1 x m2 = -1
====> The lines are perpendicular
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