Question

prove that the medians bisecting the equal sides of an isosceles triangle are also equal ​

Answer 1

In isosceles ABC

AB = AC

BN and CM are medians of side AC and AB respectively

BM = CN ( median divides the line in 2 equal parts)

In BMC and CNB

BM = CN ( proofed)

angle MBC = angle NCB ( angles of isosceles )

BC = BC ( common)

BMC is congurent to CNB by SAS

By cpct BN = CM

Hence proofed

Hope it helps you!!!

Plz mark it as brainliest....