Question

Prove that the parallelograms on equal (or same) bases and between the same parallels are equal in area.

Answer 1

draw a diagram like this....
It has two parallelograms on same base and same parallel lines
area of parallelogram ABCD = 1/2*CD*Height
= 1/2*CD*EF
area of parallelogram EDCG = 1/2*CD*Height
= 1/2*CD*GH
EF = GH As lines are parallel so distance between them is always constant.
so
area of parallelogram ABCD/area of parallelogram EDCG = 1/2*CD*EF / 1/2*CD*EF
So now by calculating
area of parallelogram ABCD = area of parallelogram EDCG


Hence,proved

Answer 2

Answer:

Step-by-step explanation :-

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