Question

PROVE THAT THE PARALLELOGRM CIRCUMSCRIBED OF A CIRCLE IS RHOMBUS​

Answer 1

Step-by-step explanation:

Given ABCD is a ||gm such that its sides touch a circle with centre O. We know that, tangents to a circle from an exterior point are equal in length. Hence, ABCD is a rhombus. ... If they are equal, then rhombus is considered as a square whose diagonals are always equal.

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Answer 2

Proof: We know that from the centre of a circle the distance to the outer circle is same means if the radius of the circle is 4cm then from center to any point on a circle will be same so the parallelogram circumscribed in a circle will be a rhombus because all sides of rhombus are equal