Math, asked by BRAINLIESTF, 7 months ago

Prove that the perimeter of a triangle is greater than the sum of three meridians​

Answers

Answered by rajvardhanpowar0311
2

Step-by-step explanation:

We know that the sum of any two sides of a triangle is greater than twice the median drawn to the third side. ∴ (AB+BC+AC)>(AD+BE+CF). Hence, the perimeter of a triangle is greater than the sum of its three medians.

Answered by kanishkmaharan98
0

Answer:

ok..................

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