prove that the perpendicular at the point of contact of the tangent to a circle passes through the centre
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Let O be the centre of the given circle. ...
∠OAB = 90° (Radius of the circle is perpendicular to the tangent)
Given ∠CAB = 90°
∴ ∠OAB = ∠CAB
This is possible only when centre O lies on the line AC. Hence, perpendicular at the point of contact to the tangent to a circle passes through the centre of the circle.
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