prove that the points (1, 9), (5, 1) and (4, 3) are collinear
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When points are collinear, then area of triangle = 0
= 1/2 |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
= x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)
= 1*(1 - 3) + 5*(3 - 9) + 4*(9 - 1)
= 1*(-2) + 5*(-6) + 4*(8)
= -2 -30 + 32
= 0
= 1/2 |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
= x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)
= 1*(1 - 3) + 5*(3 - 9) + 4*(9 - 1)
= 1*(-2) + 5*(-6) + 4*(8)
= -2 -30 + 32
= 0
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