Math, asked by saijannat, 1 year ago

Prove that the points (7,10), (-2,5) and (3,-4) are the vertices of an isosceles right triangle.

Answers

Answered by poladivyarani
1
Find the distance between ab, bc, ca by distance formula also in a isosceles triangle all sides are equal and collinear ab+bc=ac
Answered by Anonymous
6
As it is isosceles right triangle So perpendicular and base should be equal

let's fight distance between any 2 points given

(7,10) and -2,5)

√10-5)^2 + ( 7+2)^2 = √25 + 81 = √106

distance between (-2,5)( 3,-4)

√(3+2)^2 + ( -4-5)^2 = √25 +81 = √106

distance between (7,10) and (3,-4)

√(7-3)^2 + ( 10 +4)^2 = √16 + 14^2 = √196 +16

= √212

As in right angle p^2 + B^2 = H^2

106+ 106 = 212

212 = 212

As perpendicular and base are equal to √106

So its isosceles right triangle
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