Prove that the points A(-2, -1), B(1, 0) , C(4, 3) and D (1,2)are the vertices of a parallelogram ABCD.
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Let A(-2, -1), B(1, 0), C(4, 3) and D(1, 2) are the vertices of a parallelogram. Let M be the midpoint of AC, then the coordinates of M are given by Thus, AC and BD have the same midpoint. In other words, AC and BD bisect each other. Hence, ABCD is a parallelogram.
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