Question

prove that
the points A (-4, 6, 10) B(2,4,6) c (14,0-2)are collinear​

Answer 1

Let ⇒2=

k+1

14k−4

⇒14k−4=2k+2

⇒12k=6

⇒k=

2

1

and 4=

k+1

0+6

⇒4k+4=6

⇒4k=2

⇒k=

2

1

and 6=

k+1

−2k+10

⇒6k+6=−2k+10

⇒8k=4

⇒k=

2

1

⇒B(2,4,6) divides AC in 1:2

⇒ A, B, C are collinear.