prove that the points are the vertices of a right angled isosceles triangle (1, 2), (1, 5) and (4, 2)
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Therefore the given vertices of the triangle form the' Right-angled Isosceles Triangle'.
Given:
The vertices of a triangle: ( 1,2 ), ( 1,5 ), and ( 4,2 )
To Find:
The given vertices form a right-angled isosceles triangle or not.
Solution:
The given question can be solved very easily as shown below.
Given vertices of a triangle: ( 1,2 ), ( 1,5 ), and ( 4,2 )
Let Point A = ( 1,2 )
Point B = ( 1,5 )
Point C = ( 4,2 )
Let us find the distance between the points.
⇒ Distance between 2 points ( x₁, y₁ ) and ( x₂, y₂ ) = √( x₂ - x₁ )² + ( y₂ - y₁ )²
⇒ Distance between A and B = AB = √ ( 1 - 1 )² + ( 5 - 2 )²
⇒ Distance between A and B = AB = √3² = 3 units
⇒ Distance between B and C = BC = √ ( 4 - 1 )² + ( 2 - 5 )²
⇒ Distance between B and C = BC = √ 3² + ( -3 )² = 3√2 units
⇒ Distance between C and A = CA = √ ( 1 - 4 )² + ( 2 - 2 )²
⇒ Distance between C and A = CA = √ ( -3 )² = 3 units
Applying Pythagoras Theorem,
⇒ BC² = AB² + CA²
⇒ ( 3√2 )² = 3² + 3²
⇒ 9 × 2 = 9 + 9
⇒ 18 = 18
⇒ LHS = RHS
So given triangle is 'Right-angled'.
And also AB = CA = 3 units.
So the triangle is 'Isosceles'.
Therefore the given vertices of the triangle form the' Right-angled Isosceles Triangle'.
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