prove that the product of every three consecutive positive integers is divisible by 6
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according to euclids division lemma a=bq+r where r<=0
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Let the numbers be 2, 4, and 6
So, its product will be 48
Which is divisible 6 (48/6 = 8)
Hence Proven
We can also take any other example such as
Let the numbers be 8, 10 and 12
So the product will be 960
Which is divisible by 6 (960/6 = 160)
Hence Proven
Hope it helps
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So, its product will be 48
Which is divisible 6 (48/6 = 8)
Hence Proven
We can also take any other example such as
Let the numbers be 8, 10 and 12
So the product will be 960
Which is divisible by 6 (960/6 = 160)
Hence Proven
Hope it helps
Please mark as brainliest!
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