prove that the product of three consecutive positive integers is divisible by 6?
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Let the 3 consecutive positive integers be 2,3,4
then
2 × 3 × 4 = 24 ( divisible by 6 )
Again, let the three consecutive positive integers be 1,2,3
then
1×2×3=6 (divisible by 6 )
then
2 × 3 × 4 = 24 ( divisible by 6 )
Again, let the three consecutive positive integers be 1,2,3
then
1×2×3=6 (divisible by 6 )
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