Starting from rest the speed of a car increases steadily for 12 seconds while traveling a distance of 96 m, what is the speed of the car at the end of the 12 seconds
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since u=0
from 2nd equation of motion
96= 1/2 ×a ×144
a= 4/3
now put in first equation of motion
v= at = 4/3 × 12 = 16 m/s
from 2nd equation of motion
96= 1/2 ×a ×144
a= 4/3
now put in first equation of motion
v= at = 4/3 × 12 = 16 m/s
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