Question

The steam point and the ice point of a mercury thermometer are marked 80 degrees and20 degrees . What will be the temprature in centigrate mercury scale when this thermometer reads 32 degree

Answer 1

(x-20)/(80-20) =(C-0)/(100-0)

(x-20)/60=(C-0)/100

now question given ,
x=32
then ,
(32-20)/60=(C-0)/100

12/60=C/100
C=20 degree

hence in centigrade thermometer 20 degree

Answer 2

above is ans

Explanation:

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