prove that the product of two consecutive positive integers is divisible by 6
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Prove that the product of three consecutive positive integers is divisible by 6. ... if x = (2r + 1), then x + 1 = 2r + 1 + 1 = 2(r + 1)is divisible by 2. So, we can say that one of the numbers among x, x + 1 and x + 2 is always divisible by 2.
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Answer:Prove that the product of three consecutive positive integers is divisible by 6. ... if x = (2r + 1), then x + 1 = 2r + 1 + 1 = 2(r + 1)is divisible by 2. So, we can say that one of the numbers among x, x + 1 and x + 2 is always divisible by 2.
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