Prove that the rectangle circumscribing a circle is a square.
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its very easy wait for a minute I am sending you...
Step-by-step explanation:
suppose that ABCD is a rectangle so, AB = CD and AD = BC. and o is a centre.
since OP = OS ( radii of a same circle )
therefore AP = AS similarly, PB = BQ, QC = CR, RD = DS
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