Prove that the roots of the equation
(b + c-2a)x^2 + (c+ a-2b)x + (a + b-2c) = 0
are rational.
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Answer:
=(b+c-2a)x^2 + (c+a-2b)X + (a+b-2c)
IT IS IN TNE FORM OF "ax^2+bx+c=0"
.'. a= b+c-2a
b=c+a-2b
c=a+b-2c
.'.(b+c-2a)x^2 + (c+a-2b)X + (a+b-2c)= 0
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