Math, asked by knilesh7202, 10 months ago

Prove that the roots of the equation
(b + c-2a)x^2 + (c+ a-2b)x + (a + b-2c) = 0
are rational.​

Answers

Answered by silvangurram89
1

Answer:

=(b+c-2a)x^2 + (c+a-2b)X + (a+b-2c)

IT IS IN TNE FORM OF "ax^2+bx+c=0"

.'. a= b+c-2a

b=c+a-2b

c=a+b-2c

.'.(b+c-2a)x^2 + (c+a-2b)X + (a+b-2c)= 0

Answered by sprao53413
0

Answer:

Please see the attachment

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