Question

prove that the rout 7 is irrational plz solve this

Answer 1

Hi...

here is your answer:

Let √7 be rational no.

√7 = p/q ( common factor of bot p and q is 1)

p= √7q
square both side:

p^2= 7q^2

so, 7 is C.F of p^2
√7 is C.F of p

Let p^2 be 7a

(7a)^2= 7q^2

49a^2=7q^2

7a^2 = q^2

so, 7 is CF of q^2
√7 is CF of q

therefore 7 is CF of both p and q

but CF of p and q is 1

so, √7 is irrational number


hope u like my answer :-)

Answer 2

here instead of 5 you take 7...
this way you can prove root of any prime number is irrational