prove that the sides opposite to equal angles of a triangle are equal
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⬇️This is known as Isosceles triangle theorem⬇️
ABC is a given triangle with, AB=AC.
To prove: Angle opposite to AB= Angle
opposite to AC (i.e) ∠C=∠B
Construction: Draw AD perpendicular to BC
∴∠ADB=∠ADC=90⁰
Proof:
Consider △ABD and △ACD
AD is common
AB=AC
∴∠ADB=∠ADC=90⁰
Hence ∠ABD=∠ACD
∠ABC=∠ACB
∠B=∠C. Hence proved ✅
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