Question

Prove that the square of any positive integer is in the form of 3p or 3p+1

Answer 1

HOLA

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Let N be an arbitary integer

On dividing N by 3 we get quotient P and remainder R

So we have ( 3p ) , ( 3p + 1 )

By squaring we get

$( \: 3p \: ) {}^{2} = \: 9 \: which \: is \: clearly \: postive \\ \\ ( \: 3p \: + \: 1 \: ) {}^{2} = \: 9p \: + \: 1 \: clearly \: postive$
Hence any positive square integer can be of the form ( 3p ) , ( 3p + 1 )

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HOPE U UNDERSTAND ❤❤❤