Question

Prove that the sum of any 5 consecutive natural numbers is divisible by 5​

Answer 1

Answer:

The sum of any 5 consecutive integers is, in fact, evenly divisible by 5! Because n was originally defined as an integer n+2 is also an integer. Therefore, the sum of any five consecutive integers is evenly divisible by 5 and the result is an integer with no remainder.

pls mark me as brainliest.