prove that the sum of any two sides of a triangle is greater than twice the length of altitude drawn to third side
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Answer:
Given: In
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drawn from A to BC.
To prove: AB + AC > AD
Construction: Produce AD to E so that DE = AD, Join BE.
Proof:
Now in ADC and AEDB,
AD = DE (by const)
DC = BD(as D is mid-point)
ZADC = EDB (vertically opp. <S)
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