Question

PROVE THAT THE SUM OF ANY TWO SIDES OF A TRIANGLE IS GREATER THAN TWICE THE LENGTH OF THE MEDIAN DRAWN TO THE THIRD SIDE

PLS ANSWER IT FAST.............I WILL MARK IT AS BRAINLIEST

Answer 1

Answer:

see explanation

Explanation:


See Fig 1, Let D be the midpoint of BC,
⇒AD is a median of ΔABC
Now we need to prove AB+AC>2AD


See Fig2, extend AD to E such that AD=DE
⇒AE=2AD,
Draw lines BEandEC, as shown in the figure.
⇒ABEC is a parallelogram.
⇒BE=AC.
Consider ΔABE
Recall that the sum of any two sides of a triangle is greater than the length of the third side,
⇒AB+BE>AE
⇒AB+AC>2AD ....... (proved)

make the BRAINLIEST answer