Question

prove that the sum of eithey pair of
opposite angles of a cyclic quadrilateral
180°
​

Answer 1

Answer:

Let ABCD be the quadrilateral and O be the centre of the circle

angle BOD=2×angle BAD {angle subtended at the centre is twice the angle at the circumference]....(1)

angle BOD reflex ,=2×angle BCD..(2)

Add (1) and (2)

BOD + reflex BOD= 2(angle A + angle C)

360= 2( A+C)

A + C =360/2=180

Similarly you can do for angle B+D=180

(

i