Prove that the sum of rational and irrational number is always irrational
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140
Let rational number + irrational number = rational number
And we know " rational number can be expressed in the form of pq , where p , q are any integers And q 0 ,
So, we can expressed our assumption As :
pq + x = ab ( Here x is a irrational number )
x = ab - pq
So,
x is a rational number , but that contradict our starting assumption .
Hence
rational number + irrational number = irrational number ( hence proved )
And we know " rational number can be expressed in the form of pq , where p , q are any integers And q 0 ,
So, we can expressed our assumption As :
pq + x = ab ( Here x is a irrational number )
x = ab - pq
So,
x is a rational number , but that contradict our starting assumption .
Hence
rational number + irrational number = irrational number ( hence proved )
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Answered by
24
Answer: Let a be a rational number and b be an irrational
number.
Let us assume that a b + is rational, say r .
Then a b + = r
b = r a −
As r and a are both rational numbers, so r a − is a
rational number
b is a rational number.
But this contradicts that b is irrational
Hence, our assumption is wrong. Therefore, a b + is
an irrational number
i e. . the sum of a rational and an irrational number is
always an irrational number.
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