Question

prove that the sum of the squares of sides
of a rhombus is equal to the sum of the
squares of its diagonals
​

Answer 1

Answer:

Given :- A rhombus ABCD whose diagonals AC and BD intersect at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus bisect each other at right angles. ... [ In a rhombus , all sides are equal ] .

Answer 2

Answer:

Given :- A rhombus ABCD whose diagonals AC and BD intersect at O. To Prove :- ( AB² + BC² + CD² + DA² ) = ( AC² + BD² ). ➡ We know that the diagonals of a rhombus bisect each other at right angles. ... [ In a rhombus , all sides are equal