Question

a. Find the sum of 2x2 - 3y2
, 9x2 + 6y2
, -3x2 -5y2
b. Subtract (a2 + b2 + 2ab) from (a2+ b2
– 2ab)

c. Write the term containing a2 and find its coefficient

i) 16a2
– 4b2
+10
ii) 22b2
- a2
Guys help plsss​

Answer 1

Answer:

Step-by-step explanation:

a. 2x² -  3y² + 9x² + 6y² + (-3x²-5y²)

= (2x² + 9x² - 3x²) + ( -3y²+ 6y² -5y²)

= 8x² - 2y².

b) a² + b² - 2ab - (a² + b² + 2ab)

= a² + b² - 2ab - a² - b² -2ab

= -4ab.

c) i) 16a² - 4b² + 10.

      The term is 16a² and The coefficient of term a² = 16.

  ii) 22b² - a².

      The term is -a² and the coefficient of term a² = -1.