Question

Prove that the sum of two odd numbers is always even.​

Answer 1

Answer:

$\huge\mathbb{PROVING-}$

Let's first take any two odd number - 3,5

Now, let's add them= 3+5= 8

the number 8 is an even number.

Hence proved.

Answer 2

$\blue{\bold{\underline{question : - }}}$

Prove that the sum of two odd numbers is always even.

$\green{\bold{\underline{answer : - }}}$

$\it{let}$

$\boxed{{x \: and \: y \: be \: too \: odd \: number}}$

Then,

$\boxed{x = 2m + 1for \: some \: natural \: number \: m \: and \: y = 2n + 1 \: for \: some \: natural \: number \: n}$

Let's take out of their sum,

${ \implies{x + y = 2m + 1 + n = 2(m + n + 1)}}$

Here with the addition 2 in there,

$\orange{\underline{there \: for : - }}$

$\boxed{\blue{x + y \: is \: divison \: by \: 2 \: even.}}$