Question

【◆◆◆◆◆】【●●●●●】

❎❎❎❎❎❎❎

❣️❣️prove that the tangent drawn at the ends of a circle are parallel.❣️❣️

✔️✔️STEP BY STEP EXPLANTINO NEEDED✔️✔️​

Answer 1

$\huge\sf{Solution}$

Here AB is a diameter of the circle with centre O, two tangents PQ and RS drawn at points A and B respectively.

Radius will be perpendicular to these tangents.

Thus, OA ⊥ RS and OB ⊥ PQ

∠OAR = ∠OAS = ∠OBP = ∠OBQ = 90º

Therefore,

∠OAR = ∠OBQ (Alternate interior angles)

∠OAS = ∠OBP (Alternate interior angles)

Since alternate interior angles are equal, lines PQ and RS will be parallel.

Answer 2

$\huge\bf\orange{HEYA}$

____________________

$\huge\bf\pink{ANSWER}$
___________________
$<b> <i>$

Let PQ be a Diameter of the given circle with centre O.

Let AB and CD be the tangents drawn to the circle at the end points of the diameter PQ respectively.

Since tangent at a point to a circle is perpendicular to the radius through the point.

since, PQ perpendicular AB.

and PQ perpendicular CD.

=> Angle APQ= Angle PQD.

=> AB || CD. [•.• Angle APQ and Angle PQD are alternate angles.]

$\huge\bf\pink{THANKS}$



HOPE THIS HELPS.