Question

prove that the tangent of a circle at any joint on its perpendicular to the radius passes through the point of contact.​

Answer 1

Answer:

Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l. Now, OB = OC + BC. B is an arbitrary point on the tangent l. Thus, OA is shorter than any other line segment joining O to any point on l.

Explanation:

plz mark me as brainlist and plz follow me guys plz plz