Prove that the tangents drawn at the end of a diameter of a circle are parallel.
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Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively.
Radius drawn to these tangents will be perpendicular to the tangents.
Thus, OA 1 RS and OB 1 PQ
∠OAR = 90°
∠OAS = 90°
∠OBP = 90°
∠OBQ = 90°
It can be observed that
∠OAR = ∠OBQ (Alternate interior angles)
∠OAS = ∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.
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