Prove that the tangents drawn at the end point of a diameter of a circle are parallel.
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Prove that the tangents drawn at the end of a diameter of a circle are parallel. ... Let PQ be the tangent at point A & Rs be the point B. Proof: Since PQ is a tangent at point A. OA⊥ PQ(Tangent at any point of circle is perpendicular to the radius through point of contact).
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Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively.
Radius drawn to these tangents will be perpendicular to the tangents.
Thus, OA ⊥ RS and OB ⊥ PQ
∠OAR = 90º
∠OAS = 90º
∠OBP = 90º
∠OBQ = 90º
It can be observed that
∠OAR = ∠OBQ (Alternate interior angles)
∠OAS = ∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.
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